given that a b c and d are natural numbers and a=b×c×d, b=a×c×d and d=a×b×c . then find (a + b + c + b )whole square About the author Camila
Answer: abc= d= a= b, c, d= b= b= a, c, d= a= d= a, b, c= a= a+b+c+b= a+2b+c Step-by-step explanation: o-o i only used an app to solve this srry if its wrong ;-; Reply
Answer:
abc=
d=
a= b, c, d= b=
b= a, c, d= a=
d= a, b, c= a=
a+b+c+b= a+2b+c
Step-by-step explanation:
o-o i only used an app to solve this srry if its wrong ;-;