Geometry: Triangle
b) In the given figure, ZDEF = ZDHG = 50°. Prove that,
(i) ADHG – ADEF
DG GH
(ii)
EF

Geometry: Triangle
b) In the given figure, ZDEF = ZDHG = 50°. Prove that,
(i) ADHG – ADEF
DG GH
(ii)
EF
50AH
DF
EA50°
F​

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1 thought on “Geometry: Triangle<br />b) In the given figure, ZDEF = ZDHG = 50°. Prove that,<br />(i) ADHG – ADEF<br />DG GH<br />(ii)<br />EF<b”

  1. Answer:

    For triangle DEF, let the angles are x,y and z

    then x+y+z=180o

    ∠DFP=180o−x

    ∠EDQ=180o−y

    ∠FER=180o−z

    Add these three equations, we get

    ∠DFP+∠EDQ+∠FER=540o−(x+y+z)

    =540o−180o

    =360o

    Hence, ∠DFP+∠EDQ+∠FER=360o

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