ganesh took a loan of rs 25000 for 2 years at the rate of 5% per annum. Find the amount he has to repay i fthe interest if compounded half yearly About the author Alice
Answer: (i) Here, Principal (P) = Rs. 80000, Time (n) = 1\ \frac{1}{2}1 2 1 years, Rate of interest (R) = 10% Amount for 1 year (A) = P\left(1+\frac{R}{100}\right)^nP(1+ 100 R ) n = 80000\left(1+\frac{10}{100}\right)^180000(1+ 100 10 ) 1 = 80000\left(1+\frac{1}{10}\right)^180000(1+ 10 1 ) 1 = 80000\left(\frac{11}{10}\right)^180000( 10 11 ) 1 = Rs. 88,000 Interest for \frac{1}{2} 2 1 year = \frac{88000\times10\times1}{100\times2} 100×2 88000×10×1 = Rs. 4,400 Total amount = Rs. 88,000 + Rs. 4,400 = Rs. 92,400 (ii) Here, Principal (P) = Rs. 80,000 Time(n) = 1\ \frac{1}{2}1 2 1 year = 3 years (compounded half yearly) Rate of interest (R) = 10% = 5% (compounded half yearly) Amount (A) = P\left(1+\frac{R}{100}\right)^nP(1+ 100 R ) n = 80000\left(1+\frac{5}{100}\right)^380000(1+ 100 5 ) 3 = 80000\left(1+\frac{1}{20}\right)^380000(1+ 20 1 ) 3 = 80000\left(\frac{21}{20}\right)^380000( 20 21 ) 3 = 80000\times\frac{21}{20}\times\frac{21}{20}\times\frac{21}{20}80000× 20 21 × 20 21 × 20 21 = Rs. 92,610 Difference in amounts = Rs. 92,610 – Rs. 92,400 = Rs. 210 Step-by-step explanation: please make me brainlist Reply
Answer:
(i) Here, Principal (P) = Rs. 80000, Time (n) = 1\ \frac{1}{2}1
2
1
years, Rate of interest (R) = 10%
Amount for 1 year (A) = P\left(1+\frac{R}{100}\right)^nP(1+
100
R
)
n
= 80000\left(1+\frac{10}{100}\right)^180000(1+
100
10
)
1
= 80000\left(1+\frac{1}{10}\right)^180000(1+
10
1
)
1
= 80000\left(\frac{11}{10}\right)^180000(
10
11
)
1
= Rs. 88,000
Interest for \frac{1}{2}
2
1
year = \frac{88000\times10\times1}{100\times2}
100×2
88000×10×1
= Rs. 4,400
Total amount = Rs. 88,000 + Rs. 4,400 = Rs. 92,400
(ii) Here, Principal (P) = Rs. 80,000
Time(n) = 1\ \frac{1}{2}1
2
1
year = 3 years (compounded half yearly)
Rate of interest (R) = 10% = 5% (compounded half yearly)
Amount (A) = P\left(1+\frac{R}{100}\right)^nP(1+
100
R
)
n
= 80000\left(1+\frac{5}{100}\right)^380000(1+
100
5
)
3
= 80000\left(1+\frac{1}{20}\right)^380000(1+
20
1
)
3
= 80000\left(\frac{21}{20}\right)^380000(
20
21
)
3
= 80000\times\frac{21}{20}\times\frac{21}{20}\times\frac{21}{20}80000×
20
21
×
20
21
×
20
21
= Rs. 92,610
Difference in amounts
= Rs. 92,610 – Rs. 92,400 = Rs. 210
Step-by-step explanation:
please make me brainlist