from the sum of 4+3x and 5-4x + 2x square,subtract the sum of 3x square-5x and -x square+ 2x+5​

2 thoughts on “from the sum of 4+3x and 5-4x + 2x square,subtract the sum of 3x square-5x and -x square+ 2x+5​”

1. Answer:

   [tex]4 + 3 x+ 5 – 4x + 2x – \\ ( {3x}^{2} – 5x – {x}^{2} + 2x + 5) \\ = 9 + x – {2x}^{2} + 3x – 5 \\ = {2x}^{2} + 4x + 4 \\ = 2( {x}^{2} + 2x + 2)[/tex]

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2. Answer:

   2x+4=2(x+4)

   Step-by-step explanation:

   sum of 4+3x and 5-4x + 2x square, we get

   4+3x+5-4x+2x^2=2x^2-x+9—-eqn1

   sum of 3x square-5x and -x square+ 2x+5, we get

   3x^2-5x-x^2+2x+5=2x^2-3x+5—-eqn2

   eqn1-eqn2, we get

   =2x^2-x+9-(2x^2-3x+5) =2x^2-x+9-2x^2+3x-5=2x+4=2(x+4)

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