Four times the area of curved surface of a cylinder equals to 6 times the sum of its area of two bases. If it’s height is 12 cm find the curved surface area About the author Ella
Answer: curved surface area of a cylinder=(2*pi*r)*h area of two bases=(pi*r^2+pi*r^2)=2*pi*r^2 According to the given data 4(2*pi*r*h)=2(pi*r^2) by solving this r=12h/8 {Since given h=12cm) r=8cm therefore curved surface area=2*pi*8*12 =192*pi Step-by-step explanation: Reply
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Answer:
curved surface area of a cylinder=(2*pi*r)*h
area of two bases=(pi*r^2+pi*r^2)=2*pi*r^2
According to the given data
4(2*pi*r*h)=2(pi*r^2)
by solving this
r=12h/8 {Since given h=12cm)
r=8cm
therefore
curved surface area=2*pi*8*12
=192*pi
Step-by-step explanation: