four numbers are in Ap the sum of externs is 10 and the product of the means is 24 find the namber​

1 thought on “four numbers are in Ap the sum of externs is 10 and the product of the means is 24 find the namber​”

1. Answer:

   first term =5

   common difference=1

   Step-by-step explanation:

   let the numbers in the AP as a-3d, a-d, a+d, a+3d

   according to the question

   (a-3d) +(a+3d)=10

   2a=10

   a=10/2=5-) (1)

   and (a-d) (a+d) =24

   a2-d2=24

   from (1) we get 52-d2=24

   d2=25-24

   =√1=1

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