For What value of ‘x’ Which Satisfies this equation, (x-a)/(x-b)=(x+a)/(x+b) About the author Serenity
Step-by-step explanation: Let’s solve for a. x−a x−b=x+a x+b Step 1: Multiply both sides by -b+x−a+x=−ab+ax−bx+x2 b+x Step 2: Multiply both sides by b+x. −ab−ax+bx+x2=−ab+ax−bx+x2 Step 3: Add ab to both sides. −ab−ax+bx+x2+ab=−ab+ax−bx+x2+ab −ax+bx+x2=ax−bx+x2 Step 4: Add -ax to both sides. −ax+bx+x2+−ax=ax−bx+x2+−ax −2ax+bx+x2=−bx+x2 Step 5: Add -bx to both sides. −2ax+bx+x2+−bx=−bx+x2+−bx −2ax+x2=−2bx+x2 Step 6: Add -x^2 to both sides. −2ax+x2+−x2=−2bx+x2+−x2 −2ax=−2bx Step 7: Divide both sides by -2x.−2ax−2x=−2bx−2xa=b Answer a=b Reply
Step-by-step explanation:
Let’s solve for a.
x−a x−b=x+a x+b
Step 1: Multiply both sides by -b+x−a+x=−ab+ax−bx+x2 b+x
Step 2: Multiply both sides by b+x.
−ab−ax+bx+x2=−ab+ax−bx+x2
Step 3: Add ab to both sides.
−ab−ax+bx+x2+ab=−ab+ax−bx+x2+ab
−ax+bx+x2=ax−bx+x2
Step 4: Add -ax to both sides.
−ax+bx+x2+−ax=ax−bx+x2+−ax
−2ax+bx+x2=−bx+x2
Step 5: Add -bx to both sides.
−2ax+bx+x2+−bx=−bx+x2+−bx
−2ax+x2=−2bx+x2
Step 6: Add -x^2 to both sides.
−2ax+x2+−x2=−2bx+x2+−x2
−2ax=−2bx
Step 7: Divide both sides by -2x.−2ax−2x=−2bx−2xa=b
Answer
a=b