for what value of k the system of equation x+2y-3=0 and 5x+ky+7=0​

for what value of k the system of equation x+2y-3=0 and 5x+ky+7=0​

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  1. Answer:

    Thus for all real values of k other than 10, the given system of equations will have a unique solution. (ii) In order that the given system of equations has no solution, we must have: Hence, the required value of k is 10

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