For quadratic equation
[tex]10x ^{2} + 10x + 1 = 0[/tex]
What is the value of the discriminant? ​

2 thoughts on “For quadratic equation <br />[tex]10x ^{2} + 10x + 1 = 0[/tex]<br />What is the value of the discriminant? ​”

1. Answer:

   60

   Step-by-step explanation:

   10x²+10x+1=0

   a=10, b=10, c=1

   discriminate= b²-4ac

   = (10)²-4(10)(1)

   = 100-40

   =60

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2. Step-by-step explanation:

   discriminant ∆ = b² – 4ac

   [tex]a \: = 10 \: b = 10 \: \: c \: =1 \\ {b}^{2} – 4ac = {10}^{2} – 4(10)(1) \\ = 100 – 40 \\ = 60[/tex]

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