five years ago the father is 2 times the sum of the ages of his three children. after 5 years father’s age can be obtained by subt

1 thought on “five years ago the father is 2 times the sum of the ages of his three children. after 5 years father’s age can be obtained by subt”

1. Answer:

   Let us suppose that Father’s age be x years and be y years.

   Given : Case I, Five years ago, two times the sum Father’s age was of ages of his three _(i) children.

   Rightarrow x-5=2(y-15); =>x-5=2y-30; Rightarrow x-2y=-25 \

   Case II, After five years, Father’s age can 8 from the be obtained by subtracting sum of ages of the three children. = x+5=y+15-8;

   Rightarrow*-y=2 \ __(ii) Subtract equation (ii) from equation (i) we get,;

   = (x-2y)-(x-y)=-25-2; =>x-2y-x+y=-27 sum of ages of his three son’s

   Putting the value of y in equation

   (i), Rightarrow x-2*27=-25; =x=-25+54=29

   Hence,

   Present age of father is 29 years.

   Step-by-step explanation:

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