five years ago a man was old as his son, five years hence the father will be three times old as his son. Find their present ages. I’ll mark u as brainlist About the author Emery
Answer: Let Five years ago the age of son be x years and age of father be 7x years Present age of son =x+5 Present age of father =7x+5 5 years later their age will (x+10) and (7x+10) ∴7x+10=3(x+10) 7x−3x=20 4x=20 x=5 So, the present age of son=x+5=5+5=10years and the present age of father=7x+5=35+5=40years Reply
➲CORRECT QUESTION : Five years ago, a man was seven times as old as his son. Five years hence, the father will be three times as old as his son . Find their present ages. ☯GIVEN : Five years ago, the man was seven times as old as his son. Five years hence, the father will be three times as old as his son. ☯TO FIND : The present age of Father. The present age of his son. ➲SOLUTION : ✞ Let the present age of father and his son be a years and b years. According to the First Condition : Five years ago , the man was seven times as old as his son. Five years ago, Age of father = (a-5) years Age of his son = (b-5) years [tex] \implies{\sf{a-5=7(b-5)}} \\ \\[/tex] [tex]\implies{\sf{a-5=7b-35}} \\ \\ [/tex] [tex]\implies{\sf{a=7b-35+5}} \\ \\ [/tex] [tex]\implies\bf{a=7b-30….(i)}[/tex] According to the Second Condition : 5 years hence, the father will be 3 times as old as his son . Five years hence , Age of father = (a+5) years Age of son = (b+5) years [tex]\implies\sf{a+5=3(b+5)} \\ [/tex] [tex]\implies\sf{a+5=3b+15}[/tex] Substituting the value of eq(1) : [tex]\implies\sf{7b-30+5=3b+15}\\ \\ [/tex] [tex]\implies\sf{7b-25=3b+15}\\ \\ [/tex] [tex]\implies\sf{7b-3b=15+25}\\ \\[/tex] [tex]\implies\sf{4b=40}\\ \\[/tex] [tex]\implies\sf{b=\dfrac{40}{4}}\\ \\[/tex] [tex]\implies \underline{\boxed{\bf{\red{b=10}}}}[/tex] Substituting the value of b in eq(1) : [tex]\implies\sf{a=7b-30}\\ \\[/tex] [tex]\implies\sf{a=7\times10-30}\\ \\[/tex] [tex]\implies\sf{a=70-30}\\ \\[/tex] [tex]\implies\underline{\boxed{\bf{\red{a=40}}}}[/tex] [tex] \huge{ \pink{ \therefore}}[/tex] Present age of father = 40 years [tex] \huge{ \red{ \therefore}}[/tex]Present age of his son = 10 years Reply
Answer:
Let Five years ago the age of son be x years and age of father be 7x years
Present age of son =x+5
Present age of father =7x+5
5 years later their age will (x+10) and (7x+10)
∴7x+10=3(x+10)
7x−3x=20
4x=20
x=5
So, the present age of son=x+5=5+5=10years
and the present age of father=7x+5=35+5=40years
➲CORRECT QUESTION :
☯GIVEN :
☯TO FIND :
➲SOLUTION :
✞ Let the present age of father and his son be a years and b years.
According to the First Condition :
Five years ago,
[tex] \implies{\sf{a-5=7(b-5)}} \\ \\[/tex]
[tex]\implies{\sf{a-5=7b-35}} \\ \\ [/tex]
[tex]\implies{\sf{a=7b-35+5}} \\ \\ [/tex]
[tex]\implies\bf{a=7b-30….(i)}[/tex]
According to the Second Condition :
Five years hence ,
[tex]\implies\sf{a+5=3(b+5)} \\ [/tex]
[tex]\implies\sf{a+5=3b+15}[/tex]
[tex]\implies\sf{7b-30+5=3b+15}\\ \\ [/tex]
[tex]\implies\sf{7b-25=3b+15}\\ \\ [/tex]
[tex]\implies\sf{7b-3b=15+25}\\ \\[/tex]
[tex]\implies\sf{4b=40}\\ \\[/tex]
[tex]\implies\sf{b=\dfrac{40}{4}}\\ \\[/tex]
[tex]\implies \underline{\boxed{\bf{\red{b=10}}}}[/tex]
[tex]\implies\sf{a=7b-30}\\ \\[/tex]
[tex]\implies\sf{a=7\times10-30}\\ \\[/tex]
[tex]\implies\sf{a=70-30}\\ \\[/tex]
[tex]\implies\underline{\boxed{\bf{\red{a=40}}}}[/tex]
[tex] \huge{ \pink{ \therefore}}[/tex] Present age of father = 40 years
[tex] \huge{ \red{ \therefore}}[/tex]Present age of his son = 10 years