first term and the common differenceORFind the sum of all 11 terms of an A.P whose middle term is 30.171hat cor About the author Eva
Answer: 330 Step-by-step explanation: Given middle term or the sixth term is 30 As we know, an=a+(n−1)d, where a & d are the first term and common difference of an AP respectively. Then, a+5d=30 Sum = 2n(2a+(n−1)d) =211(2a+10d) Substituting, =211(2×30) =330 Reply
Answer:
330
Step-by-step explanation:
Given middle term or the sixth term is 30
As we know, an=a+(n−1)d, where a & d are the first term and common difference of an AP respectively.
Then, a+5d=30
Sum = 2n(2a+(n−1)d)
=211(2a+10d)
Substituting,
=211(2×30)
=330