Find two numbers such that one of the numbers exceeds the other number by 18
and their sum is 78.

1 thought on “Find two numbers such that one of the numbers exceeds the other number by 18<br /> and their sum is 78.”

1. ☯GIVEN :

   • Sum of two numbers = 78

   • One number is 18 more than the other.

   ☯ TO FIND :

   • The required numbers.

   ➲ SOLUTION :

   Let the one number be x.

   Then, the other number = x+18

   • One number is 18 more than the other.

   [tex]: \implies {\tt{Sum= 78}} \\ \\ [/tex]

   [tex]: \implies {\tt{One\:Number+Other\:Number= 78}} \\ \\ [/tex]

   [tex]:\implies {\tt{x +(x + 18) = 78}} \\ \\ [/tex]

   [tex]:\implies {\tt{x +x + 18 = 78}} \\ \\ [/tex]

   [tex]: \implies {\tt{2x+ 18 = 78}} \\ \\[/tex]

   [tex]: \implies {\tt{2x = 78-18}} \\ \\[/tex]

   [tex]: \implies {\tt{2x = 60}} \\ \\ [/tex]

   [tex]: \implies {\tt{x = \cancel{\dfrac{60}{2} }}} \\ \\[/tex]

   [tex]: \implies{\huge{ \underline{\boxed{ \purple{\bf{x =30}}}}}}[/tex]

   [tex]\huge{\pink{\therefore}}[/tex] One number is 30.

   [tex]\huge{\pink{\therefore}}[/tex] Other number is (30+18)=48.

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