Find the zeros iof the polynomial: (i) g(x)=x+4 (ii) p(x)=x^2+2x+1 with process About the author Hadley
Answer: Step-by-step explanation: (i) g(x)=0 ⇒x+4=0 ⇒x=-4 (ii) p(x)=0 ⇒x²+2x+1=0 ⇒x²+x+x+1=0 ⇒x(x+1)+1(x+1)=0 ⇒(x+1)(x+1)=0 ⇒x=-1 =x Reply
Answer:
Step-by-step explanation:
(i) g(x)=0
⇒x+4=0
⇒x=-4
(ii) p(x)=0
⇒x²+2x+1=0
⇒x²+x+x+1=0
⇒x(x+1)+1(x+1)=0
⇒(x+1)(x+1)=0
⇒x=-1
=x