find the zeroes of the quadratic polynomial and verify the relationship between the zeroes Z^2-3z-28​

1 thought on “find the zeroes of the quadratic polynomial and verify the relationship between the zeroes Z^2-3z-28​”

1. please mark as brainliests

   Step-by-step explanation:

   z²-3z-28

   let, p(z)=0

   z²-3z-28=0

   z²-7z+4z-28=0

   z(z-7)+4(z-7)=0

   (z-7) (z+4)=0

   [tex] \alpha = 7 \: \: \: \: \: \: \: \beta = – 4[/tex]

   here, a=1, b=-3 , c=-28

   [tex] \alpha + \beta = \frac{ – b}{a} \: \: \: \: \: \: \: \: \: \: \: \ \alpha \times \beta = \frac{c}{a} [/tex]

   7+(-4)=-(-3)/1 , 7×(-4)=-28/1

   7-4=3 , -28=-28

   3=3 ,

   hence,

   LHS =RHS

   HOPE THIS HELPS YOU ☺️

   nd PLEASE MARK IT AS BRAINLIESTS….

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