.Find the zeroes of the given quadratic polynomials and verify the relation between the zeroes and its coefficients 4×2-12 About the author Madelyn
Factorize the equation, we get (x+2)(x−4) So, the value of x 2 −2x−8 is zero when x+2=0,x−4=0, i.e., when x=−2 or x=4. Therefore, the zeros of x 2 −2x−8 are -2 and 4. Now, ⇒Sum of zeroes =−2+4=2=− 1 2 =− Coefficient of x 2 Coefficient of x ⇒Product of zeros =(−2)×(4)=−8 = 1 −8 = Coefficient of x 2 Constant term (ii) 4s 2 −4s+1 Factorize the equation, we get(2s−1)(2s−1) Reply
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Factorize the equation, we get (x+2)(x−4)
So, the value of x
2
−2x−8 is zero when x+2=0,x−4=0, i.e., when x=−2 or x=4.
Therefore, the zeros of x
2
−2x−8 are -2 and 4.
Now,
⇒Sum of zeroes =−2+4=2=−
1
2
=−
Coefficient of x
2
Coefficient of x
⇒Product of zeros =(−2)×(4)=−8 =
1
−8
=
Coefficient of x
2
Constant term
(ii) 4s
2
−4s+1
Factorize the equation, we get(2s−1)(2s−1)