find the zeroes for the quadratic equation a(x²+1) – x (a²+1)​

1 thought on “find the zeroes for the quadratic equation a(x²+1) – x (a²+1)​”

1. Answer:

   x = a or 1/a

   Step-by-step explanation:

   gn

   a(x²+1) -(a²+1) x

   to find zeros of qudratic eqn

   ax²+a-(a²+1)x =0

   x=( -b ± √b²- 4ac)/2a

   x = [a²+1 ± √ (a²+1)² -4(a)(a) ]/ 2a

   x = (a² +1 ± √ a⁴+2a²+1-4a²)/2a

   x = (a²+1± √ (a²-1)²/2a

   x = (a²+1±a²-1)/2a

   x = (a²+1+ a²-1)/2a.

   x = 2a²/2a

   x = a

   or

   x = (a²+1-a²+1) /2a

   x = 2/2a

   x = 1/a

   hence x= a or 1/a

   (x-a)(x-1/a) =0

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