find the values of a, b and c if a+b+c=0, abc=6 and(a+1)(b+1)(c+1)=0​

find the values of a, b and c if a+b+c=0, abc=6 and(a+1)(b+1)(c+1)=0​

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2 thoughts on “find the values of a, b and c if a+b+c=0, abc=6 and(a+1)(b+1)(c+1)=0​”

  1. Answer:

    [tex]a + b + c = 0 \\ (a + 1)(b + 1)(c + 1) = 0 \\ ab + b + a + 1(c + 1) = abc + bc + ca + c + ba + b + a + 1 = [/tex]

    [tex]abc + bc + ba + ac + a + b + c + 1 = 6 + \frac{6}{c} + \frac{6}{a} + \frac{6}{b} + a + b + c + 1[/tex]

    [tex]6 + \frac{6}{abc} + a + b + c + 1 = 0[/tex]

    [tex]6 + \frac{6}{6} + a + b + c + 1 = a + b + c = – 8[/tex]

    your equation has given a+b+c=0

    it’s wrong because I tried to solve this equation

    I got a+b+c=-8

    I struggle to solve for this equation

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