find the value without calculating the cubes[tex] {(28)}^{3} + {( – 15)}^{3} + {( – 13)}^{3} [/tex] About the author Maya
Answer: ╔════════♡︎═╗ \begin{gathered}{(28)}^{3} + {( – 15)}^{3} + {( – 13)}^{3} \\ = > 13 – 13 \\ = > 0(without \: calculating \: cubes)\end{gathered} (28) 3 +(−15) 3 +(−13) 3 =>13−13 =>0(withoutcalculatingcubes) \bf\huge{\pink{╚═♡︎════════╝}}╚═♡︎════════╝ \boxed{I \:Hope\: it’s \:Helpful} IHopeit ′ sHelpful Reply
[tex]\large\bf{\underline{\red{VERIFIED✔}}}[/tex] [tex]\bf\huge{\purple{╔════════♡︎═╗}}[/tex] [tex]{(28)}^{3} + {( – 15)}^{3} + {( – 13)}^{3} \\ = > 13 – 13 \\ = > 0(without \: calculating \: cubes)[/tex] [tex]\bf\huge{\pink{╚═♡︎════════╝}}[/tex] [tex]\boxed{I \:Hope\: it’s \:Helpful}[/tex] [tex]{\sf{\bf{\blue{@ℐᴛz ᴅɪɴᴜ࿐}}}}[/tex] Reply
Answer:
╔════════♡︎═╗
\begin{gathered}{(28)}^{3} + {( – 15)}^{3} + {( – 13)}^{3} \\ = > 13 – 13 \\ = > 0(without \: calculating \: cubes)\end{gathered}
(28)
3
+(−15)
3
+(−13)
3
=>13−13
=>0(withoutcalculatingcubes)
\bf\huge{\pink{╚═♡︎════════╝}}╚═♡︎════════╝
\boxed{I \:Hope\: it’s \:Helpful}
IHopeit
′
sHelpful
[tex]\large\bf{\underline{\red{VERIFIED✔}}}[/tex]
[tex]\bf\huge{\purple{╔════════♡︎═╗}}[/tex]
[tex]{(28)}^{3} + {( – 15)}^{3} + {( – 13)}^{3} \\ = > 13 – 13 \\ = > 0(without \: calculating \: cubes)[/tex]
[tex]\bf\huge{\pink{╚═♡︎════════╝}}[/tex]
[tex]\boxed{I \:Hope\: it’s \:Helpful}[/tex]
[tex]{\sf{\bf{\blue{@ℐᴛz ᴅɪɴᴜ࿐}}}}[/tex]