remainder will be zero when x² + (a + b)x + ab is divided by (x + b) we have to find the remainder when x² + (a + b)x + ab is divided by (x + b). let’s resolve x² + (a + b)x + ab into simpler form. x² + (a + b)x + ab = x² + ax + bx + ab = x(x + a) + b(x + a) = (x + a)(x + b) here we see, (x + b) is a factor of x² + (a + b) + ab, so remainder will be zero. other method : x + a ) x² + (a + b)x + ab (x + b x² + ax ___________ bx + ab bx + ab ____________ 0 hence, remainder = 0 [tex] \huge \pink {sushant2141} [/tex] Reply
remainder will be zero when x² + (a + b)x + ab is divided by (x + b)
we have to find the remainder when x² + (a + b)x + ab is divided by (x + b).
let’s resolve x² + (a + b)x + ab into simpler form.
x² + (a + b)x + ab
= x² + ax + bx + ab
= x(x + a) + b(x + a)
= (x + a)(x + b)
here we see, (x + b) is a factor of x² + (a + b) + ab, so remainder will be zero.
other method :
x + a ) x² + (a + b)x + ab (x + b
x² + ax
___________
bx + ab
bx + ab
____________
0
hence, remainder = 0
[tex] \huge \pink {sushant2141} [/tex]
Answer:
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