Answer: [tex]\huge{\mid{\overline{\underline{\fbox{\color{olive}{Answer}}}\mid}}}[/tex] ________________________________________ [tex]\large\mathfrak{\underline{\color{red}{Given}}}[/tex] [tex]\sf{x = 3}[/tex] [tex]\large\mathfrak{\underline{\color{red}{Proof}}}[/tex] [tex]\sf{:⟹ {5x}^{2} – 2 a x + 3}[/tex] [tex]\sf {:⟹ \: {(5 \times 3)}^{2} – 2 \times a \times 3 + 3 }[/tex] [tex]\sf{:⟹ {(15)}^{2} – 6a + 3 }[/tex] [tex]\sf{:⟹ \: 225 – 6a + 3}[/tex] [tex]\sf{:⟹228 – 6a = 0}[/tex] [tex]\sf{:⟹228 = 6a}[/tex] [tex]\sf{:⟹ \: a = \frac{228}{6} }[/tex] [tex]\large\sf{\color{purple}\fbox{\color{aqua}{:⟹a = 38}}}[/tex] _________________________________________ Reply
Question : Find the value of ‘a’, if 3 is a zero of polynomial 5x² – 2ax + 3 Answer : a = 8.166 Step-by-step explanation : Given : [tex]x = 3[/tex] To Find : [tex]a = ?[/tex] Solution : 5x² – 2ax + 3 Put x = 3 in the equation 5 (3)² – 2a(3) + 3 = 5 × 9 – 6a + 3 = 45 – 6a + 3 = 49 – 6a = 0 => 49 = 6a => 49/6 = a a = 8.166 ☺️☺️ Reply
Answer:
[tex]\huge{\mid{\overline{\underline{\fbox{\color{olive}{Answer}}}\mid}}}[/tex]
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[tex]\large\mathfrak{\underline{\color{red}{Given}}}[/tex]
[tex]\sf{x = 3}[/tex]
[tex]\large\mathfrak{\underline{\color{red}{Proof}}}[/tex]
[tex]\sf{:⟹ {5x}^{2} – 2 a x + 3}[/tex]
[tex]\sf {:⟹ \: {(5 \times 3)}^{2} – 2 \times a \times 3 + 3 }[/tex]
[tex]\sf{:⟹ {(15)}^{2} – 6a + 3 }[/tex]
[tex]\sf{:⟹ \: 225 – 6a + 3}[/tex]
[tex]\sf{:⟹228 – 6a = 0}[/tex]
[tex]\sf{:⟹228 = 6a}[/tex]
[tex]\sf{:⟹ \: a = \frac{228}{6} }[/tex]
[tex]\large\sf{\color{purple}\fbox{\color{aqua}{:⟹a = 38}}}[/tex]
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Question :
Find the value of ‘a’, if 3 is a zero of polynomial 5x² – 2ax + 3
Answer :
a = 8.166
Step-by-step explanation :
Given :
[tex]x = 3[/tex]
To Find :
[tex]a = ?[/tex]
Solution :
5x² – 2ax + 3
Put x = 3 in the equation
5 (3)² – 2a(3) + 3
= 5 × 9 – 6a + 3
= 45 – 6a + 3
= 49 – 6a = 0
=> 49 = 6a
=> 49/6 = a
a = 8.166
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