find the value of k so that the following pair of linear equations have 1) no solution 2) a unique solution (3k+1)x + 3y -2=0,(k

1 thought on “find the value of k so that the following pair of linear equations have 1) no solution 2) a unique solution (3k+1)x + 3y -2=0,(k”

1. Step-by-step explanation:

   Consider the given equations.

   2x+3y=7

   (k−1)x+(k+2)y=3k

   The general equations

   a1

   x+b1

   y=c1

   a2

   x+b2y=c2

   So,

   a1 =2,b1=3,c1=7a2=k−1,b2=k+2,c2=3k

   We know that the condition of infinite solution

   a 2a 1 = b 2b 1 = c 2c 1

   Therefore,

   k−12 = k+23= 3k+7⇒k−12= k+23⇒2k+4=3k−3⇒k=7

   Hence, the value of k is 7.

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