Find the value of k if one of the zeroes of the quadratic polynomial (k-1)x2 + k x + 1 is -3. About the author Bella
Answer: Step-by-step explanation: since -3 is zerof of given polynomial p(x). so, p(-3)=0 ⇒(k-1)x²+ k x + 1 =0 ⇒(k-1)×(-3)²+k×-3+1=0 ⇒9k-9-3k+1=0 ⇒6k=8 ⇒k=4/3. Reply
Answer:
Step-by-step explanation:
since -3 is zerof of given polynomial p(x).
so, p(-3)=0
⇒(k-1)x²+ k x + 1 =0
⇒(k-1)×(-3)²+k×-3+1=0
⇒9k-9-3k+1=0
⇒6k=8
⇒k=4/3.