Find the value of k for which the given equations have infinitely many solution. kx + 3y = 8; 6x + 9y = 24. About the author Sarah
Answer: Equations are kx + 3y = 8 ; 6x + 9y = 24 OR kx + 3y – 8 = 0 ; 6x + 9y – 24 = 0 a1 = k ; b1 = 3 ; c1 = -8 a2 = 6 ; b2 = 9 ; c2 = -24 a1/a2 = k/6 b1/b2 = 3/9 = 1/3 c1/c2 = -8/-24 = 8/24 = 1/3 Then condition for infinitely many solution is: a1/a2 = b1/b2 = c1/c2 k/6 = 1/3 3 × k = 6 × 1 3k = 6 k = 6/3 = 2 I hope this will help u. Please add this to the brainliest. Reply
Answer:
Equations are kx + 3y = 8 ; 6x + 9y = 24
OR
kx + 3y – 8 = 0 ; 6x + 9y – 24 = 0
a1 = k ; b1 = 3 ; c1 = -8
a2 = 6 ; b2 = 9 ; c2 = -24
a1/a2 = k/6
b1/b2 = 3/9 = 1/3
c1/c2 = -8/-24 = 8/24 = 1/3
Then condition for infinitely many solution is:
a1/a2 = b1/b2 = c1/c2
k/6 = 1/3
3 × k = 6 × 1
3k = 6
k = 6/3 = 2
I hope this will help u. Please add this to the brainliest.