Find the value of k for which
system of equation x-3y 3 and 3
-ky = 1 has a no solution​

1 thought on “<br /> Find the value of k for which<br />system of equation x-3y 3 and 3<br />-ky = 1 has a no solution​”

1. Answer:

   9

   Step-by-step explanation:

   x – 3y = 3

   a₁ = 1

   b₁ = -3

   c₁ = 3

   3x – ky = 1

   a₂ = 3

   b₂ = -k

   c₂ = 1

   If the equations have no solution,

   Then,

   [tex]\frac{a1}{a2}[/tex] = [tex]\frac{b1}{b2}[/tex] ≠ [tex]\frac{c1}{c2}[/tex]

   [tex]\frac{1}{3}[/tex] = [tex]\frac{-3}{-k}[/tex] ≠ [tex]\frac{3}{1}[/tex]

   Taking [tex]\frac{1}{3}[/tex] = [tex]\frac{-3}{-k}[/tex]

   [tex]\frac{1}{3}[/tex] = [tex]\frac{-3}{-k}[/tex]

   [tex]\frac{1}{3}[/tex] = [tex]\frac{3}{k}[/tex]

   k = 3 x 3

   k = 9

   Hope this Helps

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