Find the value of each of the following, using the column method:
2. (35)²
4. (96)²
3. (52)²
4.(96)²​

2 thoughts on “Find the value of each of the following, using the column method:<br />2. (35)²<br />4. (96)²<br />3. (52)²<br />4.(96)²​”

1. Answer:

   Step-by-step explanation:

   Given number =52

   By using column method we have.

   ∴a=5 and b=2

   a

   2

   (2×a×b) b

   2

   25 20

   4

   ​

   +2 +0

   =27 =2

   0

   ​

   ⇒52

   2

   =2704

   Steps involved in solving column method:

   Step 1: Make three columns headed by a

   2

   ,2×a×b and b

   2

   respectively. Write the values of a

   2

   ,2×a×b and b

   2

   in columns respectively.

   Step 2: In the third column underline the unit digits of b

   2

   i.e 4 and carry the tens digit of it i.e. 0 to the second column and add it to the value of the second column is 2×a×b and it will remain 20 if it added to 0.

   Step 3: In column second, underline the unit digit of the number obtained in the second step i.e. 0 and carry over the tens digit of it to the first column and add it to the value of a

   2

   i.e. 25+2=27

   Step 4: Now underline the number obtained in the third step in the first column i.e. 27. The underlined digits give the required square number.

   do the others like this

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2. Answer:

   [tex](35) {}^{2} = 1225 \\ (96) {}^{2} = 9216 \\ (52) {}^{2} = 2704 \\ (96) {}^{2} = 9216[/tex]

   Step-by-step explanation:

   ok

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