Step-by-step explanation: (2x+11) is a factor of the expression so we can write 2x=-11 and x=-11/2 now, keeping the value of x in the question, 4×3 + 20×2-tx+11 =0 4x(-11/3)3+20x(-11/2)2-tx(-11/2)+11 =0 4x-1331/8+20×121/4+11t/2+11 =0 -1331/2+605+11t/2+11=0 11t/2=1331/2-605-11 11t/2=99/2 by cross multiplying 22t=198 t=198/22 t=9 2t =2×9 2t=18 Reply
Step-by-step explanation:
(2x+11) is a factor of the expression so we can write 2x=-11
and x=-11/2
now, keeping the value of x in the question,
4×3 + 20×2-tx+11 =0
4x(-11/3)3+20x(-11/2)2-tx(-11/2)+11 =0
4x-1331/8+20×121/4+11t/2+11 =0
-1331/2+605+11t/2+11=0
11t/2=1331/2-605-11
11t/2=99/2
by cross multiplying
22t=198
t=198/22
t=9
2t =2×9
2t=18