find the surface area of a room of length 25m, height 15m and width 5m.​

find the surface area of a room of length 25m, height 15m and width 5m.​

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  1. Answer:

    l =25m

    b=5m

    h=15m

    Total surface area of rectangle = 2(lb+bh+lh)

    = 2(25×5+5×15+25×15)

    = 2(125+75+375)

    = 2×575

    = 1150m^2

    Lateral surface area of rectangle = 2(l+b)h

    = 2×30×15

    = 900m^2

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