Find the sum of first five positive consecutive integers divisible by 3 ?

Find the sum of first five positive consecutive integers divisible by 3 ?

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2 thoughts on “Find the sum of first five positive consecutive integers divisible by 3 ?<br />​”

  1. Answer:

    45

    Step-by-step explanation:

    here ,

    the first five positive intergers divisible by 3 ,

    3 , 6 , 9 , 12 , 15

    = 3 + 6 + 9 + 12 + 15

    = 45

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  2. Step-by-step explanation:

    first five positive consecutive Integers divisible by 3 = 3,6,9,12,15

    Their sum =

    3+6+9+12+15= 45

    ans= 45

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