Find the rate of intrest when rs 800 fetches rs 130 as SI in 2 yrs 6 months

2 thoughts on “Find the rate of intrest when rs 800 fetches rs 130 as SI in 2 yrs 6 months”

1. [tex]\sf Given :[/tex]

   Principal money, P = 800

   Simple interest on this money, S.I. = 130

   Time for interest, t = 2 yrs 6 months = 2.5 yrs

   To find :

   Rate of Interest, R =?

   • Formula required :

   Formula to calculate Simple interest

   [tex]➪\purple{\bigstar}\boxed{\sf{S.I.=\dfrac{P\times R \times t}{100}}}★ [/tex]

   [ Where S.I. in simple interest on Principal money P, Rate of interest per annum R and t being time for interest ]

   Solution :

   Using formula for SImple interest

   [tex]\implies\sf{S.I.=\dfrac{P \times R \times t }{100}}[/tex]

   [tex]\implies\sf{130=\dfrac{800 \times R \times 2.5 }{100}}[/tex]

   [tex]\implies\sf{130=8 \times R \times 2.5}[/tex]

   [tex]\implies\sf{130=20 \times R }[/tex]

   [tex]\implies\sf{R=\dfrac{130}{20}}[/tex]

   [tex]\implies\boxed{\boxed{\large{\purple{\sf{R=6.5\;\;\%}}}}} \;\;\;\purple{\bigstar}[/tex]

   • Therefore,

   Rate of interest is 6.5 %.

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2. Answer:

   SI = PNR/100

   P = 800 Rs

   SI = 130 Rs

   T = 2 years 6 months = 5/2 years

   130 = 800×5×R/2×100

   R = 13/2 = 6.5 % per annum

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