Given : roots of a quadratic polynomial 3 + √3 . 3 – √3 To Find : quadratic polynomial Solution: Roots 3 + √3 . 3 – √3 Sum of roots = 3 + √3 + 3 – √3 = 6 Product of roots = (3 + √3 )(3 – √3) = 9 – 3 = 6 quadratic polynomial = x² – (sum of roots)x + product of roots = x² – 6x + 6 x² – 6x + 6 is the required quadratic polynomial whose roots are 3 + root 3 and 3 minus root 3 Learn More: if 2 + root 3 and 2 minus root 3 are the two zeros of the polynomial 2 … brainly.in/question/8973942 if the product of two roots of the equation 4x^4-24x^3+31x^2+6x-8=0 … brainly.in/question/18325992 Reply
Given : roots of a quadratic polynomial
3 + √3 . 3 – √3
To Find : quadratic polynomial
Solution:
Roots
3 + √3 . 3 – √3
Sum of roots = 3 + √3 + 3 – √3 = 6
Product of roots = (3 + √3 )(3 – √3) = 9 – 3 = 6
quadratic polynomial = x² – (sum of roots)x + product of roots
= x² – 6x + 6
x² – 6x + 6 is the required quadratic polynomial whose roots are 3 + root 3 and 3 minus root 3
Learn More:
if 2 + root 3 and 2 minus root 3 are the two zeros of the polynomial 2 …
brainly.in/question/8973942
if the product of two roots of the equation 4x^4-24x^3+31x^2+6x-8=0 …
brainly.in/question/18325992
Answer:
x^2-6x+6=0
Step-by-step explanation:
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