Find the quadratic polynomial whose product andsum of zeroes are -13/5 and 3/5 respectively. About the author Valentina
Answer: The sum of the zeroes α + β = 3/5 and product of zeroes αβ = -13/5 The quadratic equation will be [tex]x^2-(\alpha +\beta )x+\alpha \beta=0[/tex] Therefore the equation is [tex]x^2-(\frac{3}{5} )x+(\frac{-13}{5}) =0[/tex] Now dividing the equation with 5 we get, [tex]5x^2-3x-13=0[/tex] is the equation. Reply
Answer:
The sum of the zeroes α + β = 3/5 and product of zeroes αβ = -13/5
The quadratic equation will be
[tex]x^2-(\alpha +\beta )x+\alpha \beta=0[/tex]
Therefore the equation is
[tex]x^2-(\frac{3}{5} )x+(\frac{-13}{5}) =0[/tex]
Now dividing the equation with 5 we get,
[tex]5x^2-3x-13=0[/tex] is the equation.