Main info :– We know that in the set of Pythagoras triplet the square of biggest number is equal the the square of other two number. Given, set of number = 4,7,8 The biggest number among these is 8 So, [tex] {8}^{2 } = 64[/tex] [tex] {7}^{2 } = 49[/tex] [tex] {4}^{2} = 16[/tex] Now , let us check 64 = 49 + 16 64 is not equal to 65 { 49+16 } ➪4,7,8 doesn’t form a Pythagoras triplet Hence , Verified ✅ Reply
Main info :– We know that in the set of Pythagoras triplet the square of biggest number is equal the the square of other two number.
Given,
set of number = 4,7,8
The biggest number among these is 8
So,
[tex] {8}^{2 } = 64[/tex]
[tex] {7}^{2 } = 49[/tex]
[tex] {4}^{2} = 16[/tex]
Now , let us check
64 = 49 + 16
64 is not equal to 65 { 49+16 }
➪4,7,8 doesn’t form a Pythagoras triplet
Hence , Verified ✅
Answer:
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