find the points on x-axis which is equidistant from P(2,-5)and Q(-2,9)​

2 thoughts on “find the points on x-axis which is equidistant from P(2,-5)and Q(-2,9)​”

1. Answer:

   Are you also marathi???????????

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2. Equidistant means the point should be mid-point.

   Let the point be R.

   [tex]P = (x1 , y1) = (2 , – 5) \\ Q =(x2, y2) = ( – 2 , 9)[/tex]

   [tex]R = ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} ) \\ \\ R = ( \frac{2 + ( – 2)}{2} \: , \: \frac{ – 5 + 9}{2} ) \\ \\ R = (\frac{2 – 2}{2} \: , \: \frac{ 4 }{2} ) \\ \\ R = (0, 2)[/tex]

   The points are R = (0 , 2 )

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