2 thoughts on “find the perimeter and diagonal of square whose length is 10 cm”
Answer:
Let □◻ABCD be the given square. l(diagonal AC) = 10 cm Let the side of the square be ‘x’ cm. In ∆ABC, ∠B = 90° [Angle of a square] ∴ AC2 = AB2 + BC2 [Pythagoras theorem] ∴ 102 = x2 + x2 ∴ 100 = 2×2 ∴ x2 = 100/2 ∴x2 = 50 ∴ x = 50−−√50 [Taking square root of both sides] = 25×2−−−−−√25×2 = 52–√52 ∴side of square is 52–√52 cm. = 4 x 52–√52 ∴ Perimeter of square = 202–√2 cmRead more on Sarthaks.com – https://www.sarthaks.com/850581/find-the-side-and-perimeter-of-a-square-whose-diagonal-is-10-cm
Answer:
Let □◻ABCD be the given square. l(diagonal AC) = 10 cm Let the side of the square be ‘x’ cm. In ∆ABC, ∠B = 90° [Angle of a square] ∴ AC2 = AB2 + BC2 [Pythagoras theorem] ∴ 102 = x2 + x2 ∴ 100 = 2×2 ∴ x2 = 100/2 ∴x2 = 50 ∴ x = 50−−√50 [Taking square root of both sides] = 25×2−−−−−√25×2 = 52–√52 ∴side of square is 52–√52 cm. = 4 x 52–√52 ∴ Perimeter of square = 202–√2 cmRead more on Sarthaks.com – https://www.sarthaks.com/850581/find-the-side-and-perimeter-of-a-square-whose-diagonal-is-10-cm
Step-by-step explanation:
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Diagonal of a square= ✓2a
where
a=side
10=✓2a
a=10/✓2a
a= 5 ✓2cm
Perimeter of square=4a
=4×5 ✓2
= 20✓2
Therefore side and perimeter of the square is 5
✓2 cm and 20 ✓2cm