find the perimeter and are of a rectangle whose length is 8m and breadth is 11 m
pls guys​

2 thoughts on “find the perimeter and are of a rectangle whose length is 8m and breadth is 11 m <br />pls guys​”

1. Answer:

   The answer will be:

   Perimeter = 38m

   Area = 88m^2.

   Step-by-step explanation:

   Perimeter of rectangle = 2(l+b)

   Thus, perimeter = 2(8 +11)

   = 2 × 19

   = 38 m

   Area of rectangle= lb

   = 8 × 11

   = 88 m^2

   That’s all.

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2. Given:

   • Length of Rectangle = 8m
   • Breadth of Rectangle = 11m

   To Find:

   • The Perimeter and Area of Rectangle

   Solution:

   ❂ [tex]\bold{Perimeter\;of\; Rectangle = 2(l+b)}[/tex]

   [tex]→\;{\sf{2(8+11)}}[/tex]

   [tex]→\;{\sf{2(19)}}[/tex]

   [tex]➝\;{\bf{38m}}[/tex]

   ❂ [tex]\bold{Area\;of\;Rectangle = l×b}[/tex]

   [tex]→\;{\sf{8×11}}[/tex]

   [tex]➝\;{\bf{88m²}}[/tex]

   AnSweR:

   Perimeter of Rectangle ◕➜ [tex]\Large{\red{\mathfrak{38m}}}[/tex]

   Area of Rectangle ◕➜ [tex]\Large{\pink{\mathfrak{88m²}}}[/tex]

   Hope It Helps You ✌️

   Reply