Find the number of years to get ₹ 1,530 as interest on a loan of ₹ 1,500 at 4% per annum. About the author Sarah
Answer: The time in which ₹1500 will amount to ₹1530 at a rate of 4% per annum is 1/2 years. Step-by-step explanation: Given that: Amount = ₹1530 Principal = ₹1500 Rate = 4% per annum To Find: Time. Let us assume: The required time be x. Finding Simple Interest: As we know that: Simple Interest = Amount – Principal Substituting the values, Simple Interest = ₹(1530 – 1500) = ₹30 Finding time: As we know that: [tex]\sf{\circ\;SI=\dfrac{P\times R\times T}{100}}[/tex] Where, P = Principal R = Rate T = Time Substituting the values, [tex]\rm{\longmapsto30=\dfrac{1500\times 4\times x}{100}}[/tex] Cutting off the zeros, [tex]\rm{\longmapsto30=\dfrac{15\!\!\!\not{0}\!\!\!\not{0}\times 4\times x}{1\!\!\!\not{0}\!\!\!\not{0}}}[/tex] [tex]\rm{\longmapsto30=15\times4\times x}[/tex] Multiplying RHS, [tex]\rm{\longmapsto30=60x}[/tex] Transposing 60 from RHS to LHS and changing its sign, [tex]\rm{\longmapsto\dfrac{30}{60}=x}[/tex] Dividing the numbers, [tex]\rm{\longmapsto\dfrac{1}{2}=x}[/tex] Hence, x = 1/2 Therefore, Required time = 1/2 years Reply
Answer:
Step-by-step explanation:
Given that:
To Find:
Let us assume:
Finding Simple Interest:
As we know that:
Substituting the values,
Simple Interest = ₹(1530 – 1500)
= ₹30
Finding time:
As we know that:
[tex]\sf{\circ\;SI=\dfrac{P\times R\times T}{100}}[/tex]
Where,
Substituting the values,
[tex]\rm{\longmapsto30=\dfrac{1500\times 4\times x}{100}}[/tex]
Cutting off the zeros,
[tex]\rm{\longmapsto30=\dfrac{15\!\!\!\not{0}\!\!\!\not{0}\times 4\times x}{1\!\!\!\not{0}\!\!\!\not{0}}}[/tex]
[tex]\rm{\longmapsto30=15\times4\times x}[/tex]
Multiplying RHS,
[tex]\rm{\longmapsto30=60x}[/tex]
Transposing 60 from RHS to LHS and changing its sign,
[tex]\rm{\longmapsto\dfrac{30}{60}=x}[/tex]
Dividing the numbers,
[tex]\rm{\longmapsto\dfrac{1}{2}=x}[/tex]
Hence,
Therefore,