find the length of the longestrod that can be put in a roomof dimension 20m x 20m x 20m. About the author Madeline
Answer: The length of the longest rod that can place in room is 30 meters Step-by-step explanation: Given as : The dimension of the room Length of room = L = 20 meters Breadth of room = B = 20 meters Height of the room = H = 10 meters Let The length of the longest rod that can place in room = L’ According to question The length of the longest rod that can place in room = Diagonal of the room ∵ Diagonal of room = \sqrt{Lenght^{2} + breadth^{2} +height^{2} } Lenght 2 +breadth 2 +height 2 So, The length of the longest rod that can place in room = \sqrt{L^{2}+B^{2}+H^{2} } L 2 +B 2 +H 2 Or, L’ = \sqrt{20^{2}+20^{2}+10^{2} } 20 2 +20 2 +10 2 Or, L’ = \sqrt{400+400+100} 400+400+100 Or, L’ = \sqrt{900} 900 Or, L’ = 30 meters ∴ The length of the longest rod that can place in room = L’ = 30 meters Hence, The length of the longest rod that can place in room is 30 meters Step-by-step explanation: mark me brainlist Reply
Answer:
The length of the longest rod that can place in room is 30 meters
Step-by-step explanation:
Given as :
The dimension of the room
Length of room = L = 20 meters
Breadth of room = B = 20 meters
Height of the room = H = 10 meters
Let The length of the longest rod that can place in room = L’
According to question
The length of the longest rod that can place in room = Diagonal of the room
∵ Diagonal of room = \sqrt{Lenght^{2} + breadth^{2} +height^{2} }
Lenght
2
+breadth
2
+height
2
So, The length of the longest rod that can place in room = \sqrt{L^{2}+B^{2}+H^{2} }
L
2
+B
2
+H
2
Or, L’ = \sqrt{20^{2}+20^{2}+10^{2} }
20
2
+20
2
+10
2
Or, L’ = \sqrt{400+400+100}
400+400+100
Or, L’ = \sqrt{900}
900
Or, L’ = 30 meters
∴ The length of the longest rod that can place in room = L’ = 30 meters
Hence, The length of the longest rod that can place in room is 30 meters
Step-by-step explanation:
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