Find the length of the base of a triangle whose area is 440m2 and altitude is 11m •​

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1. Question :

   Find the length of the base of a triangle whose area is 440m² and altitude is 11m .

   Answer :

   [tex]\bf\pink{Given:}[/tex]

   • Area of a triangle is 440 m² .

   • Height of the triangle is 11 m .

   [tex]\bf\pink{To\:find:}[/tex]

   • Base of the triangle ?

   Explanation :

   [tex]\sf\purple{ Area\:of\:triangle = \dfrac{1}{2}\times b\times h }[/tex]

   • b means base .

   • h means height .

   [tex]\\ \longrightarrow\sf{ 440 = \dfrax{1}{2}\times b\times 11}[/tex]

   [tex]\\ \longrightarrow\sf{ 440\times 2 = 11b}[/tex]

   [tex]\\ \longrightarrow\sf{ 880 = 11b}[/tex]

   [tex]\\ \longrightarrow\sf{b = \dfrac{880}{11}}[/tex]

   [tex]\\ \longrightarrow\sf{b = 80}[/tex]

   Therefore the base is 80 m .

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