find the least Number which when divided
by 6, 15, and 18 leaves bemainder 5 in
Cach
case​

1 thought on “find the least Number which when divided<br />by 6, 15, and 18 leaves bemainder 5 in<br />Cach<br />case​”

1. Answer:

   95

   Step-by-step explanation:

   Find least common multiple i.e. L.C.M of 6, 15 , 18

   L.C.M(6, 15 ,18) = 90

   which is the smallest no divisible by all given numbers 6 , 15 , 18

   so to get remainder as 5 just add 5 to 90 i.e. 90+5 = 95

   hence , 95 is the lest number which when divided by 6 , 15 , 18 leaves remainder 5 in each case.

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