find the least number when divided by 6 , 15 and 18 and leaves the remainder 2 in each case

Question

Reagan · Answer

Answer:   Therefore, the required number = 90+5 = 95  As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.

Eloise

Find the possible values of tan x, if cos2x + 5 sin x. cos x = 3.

1. Draw different pairs of circles. How many points does each pair have in common?
What is the maximum number of common point

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