Find the general term of A.P. whose sum of n terms is given by 4n+ 3n​

Find the general term of A.P. whose sum of n terms is given by 4n+ 3n​

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Audrey

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  1. Answer:

    put (n=1) for sum of first ,n=2 for second ,n=3 for third and so on.

    S1 =4(1)+3(1)

    =7

    S2=4(2)+3(2)

    =14

    you can find d by only two but for making conform that it is an AP so I am also taking 3rd

    S3=4(3)+3(3)

    =21

    now ,a is sum of first much

    and A2 =S2-S1

    =7

    A3= S3-S2

    = 7

    you can se that common difference is zero

    d= a2-a1

    =7-7

    =0

    hence, AP

    7,7,7,7,7

    Sorry, I don’t explain properly, please don’t mind

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