Find the equation of the tangent line to the curve
y= 4x/1+x² at the point (4,16/17). The equation of this tangent line

1 thought on “Find the equation of the tangent line to the curve<br />y= 4x/1+x² at the point (4,16/17). The equation of this tangent line<br />”

1. Answer:

   The slope of the tangent given is its derivative

   on applying differentiation to 4x/1+x^2

   u will get (4 – 4x^2)/((x^2+1)^)2

   on substituting x = 4

   u will get -60/289

   which is the slope

   therefore we can use slope point form and write

   m(x-4) = (y-16/17)

   -60/289(x-4) = y – 16/17

   therefore y = (-60/289)x + 256/149

   Reply