Find the equation of the
perpendicular

bisector of the line joining the points

(0,0) and (-3,4)​

2 thoughts on “Find the equation of the<br /> perpendicular <br /><br />bisector of the line joining the points <br /><br />(0,0) and (-3,4)​”

1. Answer:

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2. Answer:

   Answer

   Correct option is

   C

   6x+4y=1

   A(1,2) and B(−2,0) are given point

   ∴ midpoint p=(

   2

   1+(−2)

   ,

   2

   2+0

   )

   ∴ midpoint p=(

   2

   −1

   ,1)

   Also slope of AB=

   −2−1

   0−(2)

   =

   −3

   −2

   ∴ slope of AB=

   3

   2

   slope of line perpendicular to AB=

   3

   2

   −1

   =

   2

   −3

   ∴ equation of perpendicular bisector

   y−1=

   2

   −3

   (x+

   2

   1

   )

   ∴y−1=

   2

   −3

   (x+

   2

   1

   )

   ∴2y−2=−3(x+

   2

   1

   )

   ∴4y−4=−3(2x+1)

   ∴4y−4=−6x−3

   ∴4y+6x−4+3=0

   6x+4y−1=0

   ∴ equation of line 6x+4y−1=0

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