Find the equation of straight line passing through (3, 5) and perpendicular to the line 6x + 2y = 7

1 thought on “Find the equation of straight line passing through (3, 5) and perpendicular to the line 6x + 2y = 7”

1. Answer:

   6x+2y=7

   The line perpendicular to above eqn is

   2x-6y+k=0

   As line passes through (3,5)

   2×3-6×5+k=0

   6-30+k=0

   k=24

   So the required equation is 2x-6y=24 or x-3y=12

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