find the discriminant of the equation 3×2=5x+2=0 and hence write the nature of its roots About the author Alaia
Step-by-step explanation: D = 0, Roots are real and equal 3 1 , 3 1 Nature of the roots of a quadratic equation is determined by its discriminant D=b 2 −4ac Comparing 3x 2 −2x+ 3 1 =0 with ax 2 +bx+c=0 we get a=3,b=−2,c= 3 1 Therefore D=b 2 −4ac =(−2) 2 −4×3× 3 1 =4−4 =0 Therefore roots are real and equal. Therefore roots are, 2a −b± b 2 −4ac = 2×3 −(−2)± (−2) 2 −4×3× 3 1 = 2×3 2±0 = 2×3 2 = 3 1 Therefore roots are 3 1 , 3 1 Reply
Step-by-step explanation: D = 0, Roots are real and equal
3
1
,
3
1
Nature of the roots of a quadratic equation is determined by its discriminant D=b
2
−4ac
Comparing 3x
2
−2x+
3
1
=0 with ax
2
+bx+c=0 we get a=3,b=−2,c=
3
1
Therefore D=b
2
−4ac
=(−2)
2
−4×3×
3
1
=4−4
=0
Therefore roots are real and equal.
Therefore roots are,
2a
−b±
b
2
−4ac
=
2×3
−(−2)±
(−2)
2
−4×3×
3
1
=
2×3
2±0
=
2×3
2
=
3
1
Therefore roots are
3
1
,
3
1