Find the difference between compound interest and simple interest on Rs 12000 and in 1 1/2 years at 10 % compounded half yearly. About the author Adeline
Answer: Step-by-step explanation: Given : P = Rs 12,000; n = 1 2 1 years and r = 10% S.I.= 100 P×R×T = 100 12,000×10× 2 3 =Rs1,800 To calculate C.I. For 1 year P = Rs 12,000; n = 1 years and r = 10% C.I.=P(1+ 100 r ) n =12,000(1+ 100 10 ) 1 =Rs13,200 For next 1/2 year P = Rs 13,200; n = 1/2 year and r = 10% C.I.=P(1+ 2×100 r ) 2×n =13,200(1+ 2×100 10 ) 2 1 ×n =13,200( 20 21 ) 1 = Rs 13,860 ∴ C.I. = Rs 13,860 – Rs 12,000 = Rs 1,860 ∴ Difference between C.I. and S.I. = Rs 1,860 – Rs 1,800 = Rs 60 Reply
Answer:
Step-by-step explanation:
Given : P = Rs 12,000; n = 1
2
1
years and r = 10%
S.I.=
100
P×R×T
=
100
12,000×10×
2
3
=Rs1,800
To calculate C.I. For 1 year
P = Rs 12,000; n = 1 years and r = 10%
C.I.=P(1+
100
r
)
n
=12,000(1+
100
10
)
1
=Rs13,200
For next 1/2 year
P = Rs 13,200; n = 1/2 year and r = 10%
C.I.=P(1+
2×100
r
)
2×n
=13,200(1+
2×100
10
)
2
1
×n
=13,200(
20
21
)
1
= Rs 13,860
∴ C.I. = Rs 13,860 – Rs 12,000 = Rs 1,860
∴ Difference between C.I. and S.I.
= Rs 1,860 – Rs 1,800 = Rs 60
Answer:
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