find the co ordinates of point (-2, 6), (3, -4) in the ratio 2:3​

1 thought on “find the co ordinates of point (-2, 6), (3, -4) in the ratio 2:3​”

1. let the point needed be of the form (x , y)

   no , by section formula , we get:–

   x = m1x2 + m2x1/ m1 + m2 , y = m1y2 + m2y1/m1 + m2

   x = 2*3 + 3*-2/2+3 , y = 2*-4 + 3*6/2 + 3

   ____answered by advik190______

   x = (6 – 6)/5 , y = -8 + 18/5

   x= 0 , y = 2

   therefore the required point will be (0,2)

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