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Find the area of triangle whose vertices are A. (4,3) B. (6,8) C. (2,6)​

By Mackenzie

Find the area of triangle whose vertices are A. (4,3) B. (6,8) C. (2,6)​

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Mackenzie

) Identify the correct step .


a) sin (105) cos60 cos45 sin 60 sin45

b)cos(105) cos60 cos45 sin 60 sin4


The discriminant of a quadratic equation with integer coefficients cannot
4762
be
1) 23
2) 24
3) 25

1 thought on “Find the area of triangle whose vertices are A. (4,3) B. (6,8) C. (2,6)​”

  1. Answer:

    x1=4,y1=3

    x2=6 ,y2=8

    x3=2, y3=6

    area of=1/2[x1(y2-y3) + x2(y3-y1) + x3(y1-y2)]

    =1/2[4*(8-6)+6*(6-3)+2*(3-8)]

    =1/2[4*2+6*3+2*(-5)]

    =1/2[8+18-10]

    =1/2[26-10]

    =1/2[16]

    =8

    answer is 8

    hope it will help u!!!!

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