Find the area
and circumference of circle
whose radius is 28m​

2 thoughts on “Find the area<br />and circumference of circle<br /> whose radius is 28m​”

1. [tex] \bf \: Given \: : [/tex] ↴

   [tex] \sf \: Radius \: of \: the \: circle \: : \: 28 \: meter.[/tex]

   [tex] \bf \: To \: find \: : [/tex] ↴

   [tex] \sf \: Area \: and \: circumference \: of \: circle.[/tex]

   [tex] \bf \: So, \: Let’s \: Start \: : [/tex] ↴

   [tex] \sf \: First \: of \: all \: we \: will \: find \: the \: circumference \: of \: the \: circle. [/tex]

   [tex] \boxed{{ \purple{ \sf \: Circumference \: of \: the \: circle \: : \: 2πr }}}[/tex]

   [tex] \sf \: Putting \: the \: value \: : [/tex] ↴

   [tex] \bf \longrightarrow \: 2 \: \times \: \dfrac{22}{7} \: \times 28[/tex]

   [tex] \bf \longrightarrow \: \dfrac{1232}{7} [/tex]

   [tex] \bf \longrightarrow \: 176 \: m ^{2} [/tex]

   [tex] \blue{\sf \: So, \: the \: Circumference \: of \: the \: circle : 176 \: m ^{2} }[/tex]

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   [tex] \sf \: Now, \: we \: will \: find \: the \: area \: of \: the \: circle.[/tex]

   [tex] \boxed{ \purple{ \sf \: Area \: of \: the \: Circle : πr ^{2} }}[/tex]

   [tex] \sf \: Putting \: the \: value \: : [/tex] ↴

   [tex] \bf \longrightarrow \: \: \dfrac{22}{7} \: \times 28 ^{2}[/tex]

   [tex] \bf \longrightarrow \: \: \dfrac{22}{7} \: \times 28 \: \times 28[/tex]

   [tex] \bf \longrightarrow \: \dfrac{17248}{7} [/tex]

   [tex] \bf \longrightarrow \: 2464 \: m ^{2} [/tex]

   [tex] \blue{\sf \: So, \: the \: area \: of \: the \: circle : 2464 \: m ^{2} }[/tex]

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2. Let r be the radius of the circle.

   Then according to the problem we’ve r=28m.

   Then perimeter will be (P)=2πr

   (P) = 2×(22÷7)×28

   (P) = 176m

   So the perimeter of the circle is 176m.

   (A) = π(r)^2

   (A) = (22÷7)×(28)^2

   (A) = 22÷7)×28×28

   (A) = (22÷7)×784

   (A) = (22×784)÷7

   (A) = 17248÷7

   (A) = 2464m

   So the area is 2464m.

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